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composer
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Add source package name to debug info when enabling plugins

pull/9793/head
Jordi Boggiano 2021-03-16 20:30:53 +01:00
parent 3b89a9c3b4
commit 63c086c208
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GPG Key ID: 7BBD42C429EC80BC
1 changed files with 12 additions and 4 deletions
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16
src/Composer/Plugin/PluginManager.php
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@ -229,7 +229,7 @@ class PluginManager
$this->registeredPlugins[$package->getName()] = $installer;
} elseif (class_exists($class)) {
$plugin = new $class();
$this->addPlugin($plugin, $isGlobalPlugin);
$this->addPlugin($plugin, $isGlobalPlugin, $package);
$this->registeredPlugins[$package->getName()] = $plugin;
} elseif ($failOnMissingClasses) {
throw new \UnexpectedValueException('Plugin '.$package->getName().' could not be initialized, class not found: '.$class);
@ -319,11 +319,19 @@ class PluginManager
* programmatically and want to register a plugin class directly this is a valid way
* to do it.
*
* @param PluginInterface $plugin plugin instance
* @param PluginInterface $plugin plugin instance
* @param ?PackageInterface $sourcePackage Package from which the plugin comes from
*/
public function addPlugin(PluginInterface $plugin, $isGlobalPlugin = false)
public function addPlugin(PluginInterface $plugin, $isGlobalPlugin = false, PackageInterface $sourcePackage = null)
{
$this->io->writeError('Loading plugin '.get_class($plugin).($isGlobalPlugin ? ' (installed globally)' : ''), true, IOInterface::DEBUG);
$details = array();
if ($sourcePackage) {
$details[] = 'from '.$sourcePackage->getName();
}
if ($isGlobalPlugin) {
$details[] = 'installed globally';
}
$this->io->writeError('Loading plugin '.get_class($plugin).($details ? ' ('.implode(', ', $details).')' : ''), true, IOInterface::DEBUG);
$this->plugins[] = $plugin;
$plugin->activate($this->composer, $this->io);